Fraction Algebra Problem
- Thread starter Jason76
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D
Deleted member 4993
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Write those as fractions - cross-multiply - solve
\(\displaystyle \dfrac{\dfrac{3}{4}t^{-1/4}}{t^{-1/4}} = \dfrac{\dfrac{1}{4}t^{-1/3}}{t^{-1/4}}\)
\(\displaystyle \dfrac{3}{4} = \dfrac{1}{4}t^{-1/12}\)
\(\displaystyle \dfrac{12}{4} = t^{-1/12}\)
\(\displaystyle \dfrac{3}{1} = t^{-1/12}\) Next move?
\(\displaystyle \dfrac{3}{4} = \dfrac{1}{4}t^{-1/12}\)
\(\displaystyle \dfrac{12}{4} = t^{-1/12}\)
\(\displaystyle \dfrac{3}{1} = t^{-1/12}\)
Next move?
Last edited:
D
Deleted member 4993
Guest
\(\displaystyle \dfrac{\dfrac{3}{4}t^{-1/4}}{t^{-1/4}} = \dfrac{\dfrac{1}{4}t^{-1/3}}{t^{-1/4}}\)
\(\displaystyle \dfrac{3}{4} = \dfrac{1}{4}t^{-1/12}\)
\(\displaystyle \dfrac{12}{4} = t^{-1/12}\)
\(\displaystyle \dfrac{3}{1} = t^{-1/12}\)
t1/12 = 1/3 ..... now your move...