Formular problem, Need help.

[cnx42]

Hi, need help on Formula problem solving. I can have A B C but I don't know how to find D.



Here is the way to find A B C.

From first table.

A = 7-1 =6
B = 7-6 =1
C = 7 + A = 7 + 6 = 13

Appreciated for helping.

 

[stapel]

Hi, need help on Formula problem solving. I can have A B C but I don't know how to find D.

View attachment 5276

Are we supposed to assume that all the squares use the same formula to arrive at their values? If so, then:

Here is the way to find A B C.

From first table.

A = 7-1 =6
B = 7-6 =1
C = 7 + A = 7 + 6 = 13

From the second square, following your proposed formula:

A = 3 - 7 = -4 (wrong)
B = 3 - 2 = 1 (wrong)
C = 3 + A = -1 (wrong)

Please clarify how you obtained your values for A, B, and C. Thank you!

 

[cnx42]

Are we supposed to assume that all the squares use the same formula to arrive at their values? If so, then:


From the second square, following your proposed formula:

A = 3 - 7 = -4 (wrong)
B = 3 - 2 = 1 (wrong)
C = 3 + A = -1 (wrong)

Please clarify how you obtained your values for A, B, and C. Thank you!

NO it's correct. But If X < Y need adding 10 on X. So,

Table#2
A = 3 - 1 = 2
B = 13-6= 7

Table#3
A 5 - 1 = 4
B = 13-6= 9

Table#4
A = 8 - 1 = 7
B = 8-6= 2

 

[stapel]

NO it's correct. But If X < Y need adding 10 on X. So,

Table#2
A = 3 - 1 = 2
B = 13-6= 7

Table#3
A 5 - 1 = 4
B = 13-6= 9

If every table uses a different rule, then there is no possible way to find "the" values of the variables, since we can make up any rule we feel like. :shock:

Table#4
A = 8 - 1 = 7
B = 8-6= 2

There is no "1" in the fourth table. How are you getting your values?

Please reply with a clear explanation of the logic you are using. Thank you!