Formula for nth term

[Teakskier]

Can someone give me the formula for the nth term of a series where

xn = xn-1 x (n+1)/(n+2)

Any help on the answer and how to derive is much appreciated

 

[Deleted member 4993]

Can someone give me the formula for the nth term of a series where

xn = xn-1 x (n+1)/(n+2)

Any help on the answer and how to derive is much appreciated

Please use '*' to indicate multiplication to avoid confusion with the variable 'x'

You ask for:

the formula for the nth term of a series​

However, the formula for n th term is already given. The form of the given formula is called recursive form.

Please clarify your query.

 

[Teakskier]

Yes, thanks Subhotosh, you are correct. Please use the multiplication instead of the X. And yes this is the recursive form and I need the general for in terms of n only (and X0 )

 

[Teakskier]

xn = xn-1 *(n+1)/(n+2)

Please give the general form not in recursive form

 

[Dr.Peterson]

Can someone give me the formula for the nth term of a series where

xn = xn-1 x (n+1)/(n+2)

Any help on the answer and how to derive is much appreciated

You're looking for an explicit formula for x_n.

Write out expressions for the first few terms; e.g. if `x_0 = a`, then `x_1 = a(2/3)`, `x_2 = a(2/3)(3/4)`, and so on. Do you see a pattern?

 

[Teakskier]

You're looking for an explicit formula for x_n.

Write out expressions for the first few terms; e.g. if `x_0 = a`, then `x_1 = a(2/3)`, `x_2 = a(2/3)(3/4)`, and so on. Do you see a pattern?

Thanks. I hadn't attempted it as was in a hurry! I thought it would be complicated like Fibonacci nth term.

 

[Dr.Peterson]

Thanks. I hadn't attempted it as was in a hurry! I thought it would be complicated like Fibonacci nth term.

Always try something before giving up! Sometimes optimism is justified.

 

[Steven G]

Instead of trying something you took the time to post here instead. I wish that I had that much free time.