foiling with exponents (4d^(1/2) + 1)(2d^(1/2)-3)

[timpickens]

(4d^(1/2) + 1)(2d^(1/2)-3)

so far i've got:

8d-12d^(1/2)+2d^(1/2)-3

8d-10D^1/2 - 3


any help would be greatly appreciated!

 

[stapel]

I don't see anything else you can do with this. If the instructions were to multiply it out, I think you're done.

Eliz.

P.S. Thank you for showing your work!!

 

[jsbeckton]

Whats the problem, thats what i got, you did the foil operation and reduced, what else is the question asking for?

 

[timpickens]

my bad

haha, i'm dumb! for some reason i was thinking 10d^1/2 could somehow subtract 8d.

sorry to waste your time, guys. but thanks!

 

[stapel]

for some reason i was thinking 10d^1/2 could somehow subtract 8d.

If it helps (and it often helps me), convert the "to the one-half power" to "the square root of":

. . . . .(4 sqrt[d] + 1)(2 sqrt[d] - 3)

. . . . .8d + 2 sqrt[d] - 12 sqrt[d] - 3

. . . . .8d - 10 sqrt[d] - 3

That can sometimes make the meaning a little more intuitive, so you can be sure that you're "done". :wink:

Eliz.

 

[timpickens]

for some reason i was thinking 10d^1/2 could somehow subtract 8d.

If it helps (and it often helps me), convert the "to the one-half power" to "the square root of":

. . . . .(4 sqrt[d] + 1)(2 sqrt[d] - 3)

. . . . .8d + 2 sqrt[d] - 12 sqrt[d] - 3

. . . . .8d - 10 sqrt[d] - 3

That can sometimes make the meaning a little more intuitive, so you can be sure that you're "done". :wink:

Eliz.

Excellent man, i appreciate it! :wink: