First Principles

Idealistic

Junior Member
Joined
Sep 7, 2007
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I'm familiar with finding the derivative via first principles of basic functions like y = x^2 and such but would like to see how the derivative is calculated in slightly more complex functions like: y = x^2 + 3x + 2.

I know the formula is lim/h-->0 f(x + h) - f(x)/h but im unsure how to incorperate a function like above into this formula.
 
Idealistic said:
I'm familiar with finding the derivative via first principles of basic functions like y = x^2 and such but would like to see how the derivative is calculated in slightly more complex functions like: y = x^2 + 3x + 2.

I know the formula is lim/h-->0 f(x + h) - f(x)/h but im unsure how to incorperate a function like above into this formula.
If you can do f(x) = x and g(x) = x[sup:26qn283z]2[/sup:26qn283z], then there shouldn't be any difficulty in doing h(x) = x[sup:26qn283z]2[/sup:26qn283z] + 3x + 2, since everything works in exactly the same way. Where are you stuck?

Please be complete. Thank you! :D

Eliz.
 
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