First and Second derivative: h(x)= x[square root of (9 - x)]

[jory543]

h(x)= x[square root of (9 - x^2)]
I'm having trouble finding the first and second derivatives.
Ok i think im on track with the product rule, but im not sure
I got h'(x)= 1/2 x[(9-x^2)^-1/2](-2x) and thats where im stuck, i think i need more but im not sure what more i need.

 

[Deleted member 4993]

Re: First and Second derivative

h(x)= x[square root of (9 - x^2)]
I'm having trouble finding the first and second derivatives.

Use the product rule:

u(x) = x

v(x) =sqrt(9-x[sup:13ens9oi]2[/sup:13ens9oi])

dh/dx = u * dv/dx + v * du/dx

Please show us your work, indicating exactly where you are stuck - so that we know where to begin to help you.