Finding velocity from height question?

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fry10fry10

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The height (in feet) of a skydiver at time t (in seconds) after opening his parachute is given below. Find the skydiver's velocity after the parachute opens.
h(t) = 2000 – 13t
 
^No that is not the right answer. I thought that, but the computer said that 2000 feet/sec is not the velocity.
 
Take the derivative. dh/dt = v(t).

Kind of an odd/over-simplified model.
 
When the parachute opens - assumption is that the particle goes into "terminal velocity".
 
fry10fry10 said:
^No that is not the right answer. I thought that, but the computer said that 2000 feet/sec is not the velocity.
Click to expand...
Whoops. I tdoes say "velocity", doesn't it?
 
fry10fry10 said:
The height (in feet) of a skydiver at time t (in seconds) after opening his parachute is given below. Find the skydiver's velocity after the parachute opens.
h(t) = 2000 – 13t
Click to expand...

dh/dt = -13 ft/sec
 
Thanks guys for all your help. I found out that the answer is actually -13 ft/s, becuase he is falling down.
 
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