Finding third coordinate on triangle.

rousie313

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Dec 1, 2009
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Im working on a project for my Calc 3 class and need help finding the third coordinate of and obtuse triangle that i made out of connecting three cities on a map. I know the 3 distances from the points I designated as A,B, and C. The distance from A to B=1362. The distance from B to C=863. The distance from A to C=821. Im calling point A the origin(0,0) and figured out the point B must be (1392,0). I need to know how to find point C with the given information. Any help appreciated. Thank you!
 
If A is at the origin, then the coordinates you have for B lie on the x axis. If B does lie on the x axis, then its coordinates would be

(1362,0), not (1392,0). Unless that is a typo?.

Do you have a diagram you could post. That would help. The triangle could be oriented most any way. In order to find the

coordinates, a diagram would prove useful.

You could draw one in Paint, then use the Upload Attachment link to post the picture you make.
 
Yes that B coordinate was a typo sorry it was supposed to be 1362. The paint file i enclosed was the best i could do. That top angle where point C is that i need to find is in fact obtuse even if it looks like a right angle in my drawing.
 
rousie313 said:
Yes that B coordinate was a typo sorry it was supposed to be 1362. The paint file i enclosed was the best i could do. That top angle where point C is that i need to find is in fact obtuse even if it looks like a right angle in my drawing.

Assume C is at (x[sub:y2s3jr6m]1[/sub:y2s3jr6m],y[sub:y2s3jr6m]1[/sub:y2s3jr6m])

Then

x[sub:y2s3jr6m]1[/sub:y2s3jr6m][sup:y2s3jr6m]2[/sup:y2s3jr6m] + y[sub:y2s3jr6m]1[/sub:y2s3jr6m][sup:y2s3jr6m]2[/sup:y2s3jr6m] = 821[sup:y2s3jr6m]2[/sup:y2s3jr6m]


[x[sub:y2s3jr6m]1[/sub:y2s3jr6m]-1362][sup:y2s3jr6m]2[/sup:y2s3jr6m] + y[sub:y2s3jr6m]1[/sub:y2s3jr6m][sup:y2s3jr6m]2[/sup:y2s3jr6m] = 863[sup:y2s3jr6m]2[/sup:y2s3jr6m]

Two equations - two unknowns - solve it
 
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