Finding the vertex of a parabola?

[discreditedvalidity]

x² + 8y = 0

That is the equation. How do you find the vertex algebraically? Thanks.

 

[daon]

x² + 8y = 0

That is the equation. How do you find the vertex algebraically? Thanks.

Equation of a parabola: \(\displaystyle y = ax^2 + bx + c\)

Given your equation: \(\displaystyle x^2 + 8y = 0\Rightarrow y = -\frac{x^2}{8}\)

Your a = -\(\displaystyle \frac{1}{8}\), b = \(\displaystyle 0\), c = \(\displaystyle 0\).

The vertex of a parabola is given by \(\displaystyle \frac{-b}{2a}\)