Finding the vertex of a parabola?

[discreditedvalidity]

x² + 8y = 0

That is the equation. How do you find the vertex algebraically? Thanks.

 

[daon]

x² + 8y = 0

That is the equation. How do you find the vertex algebraically? Thanks.

Equation of a parabola: $\displaystyle y = ax^2 + bx + c$

Given your equation: $\displaystyle x^2 + 8y = 0\Rightarrow y = -\frac{x^2}{8}$

Your a = -$\displaystyle \frac{1}{8}$, b = $\displaystyle 0$, c = $\displaystyle 0$.

The vertex of a parabola is given by $\displaystyle \frac{-b}{2a}$