Finding the value of m in a given function

[IBstudent]

Let the function he be defined by h(x) = 14 + (x^2 / 4)
If h(2m) = 9m, what is one possible value of m?

My (wrong) approach:

14 + (2x^2 /4) = 9m
.
.
.
.
2x^2 -36x + 56 = 0
(then find the values of x)

This is wrong and the values aren't ever close...

Please help :S

 

[lookagain]

Let the function he be defined by h(x) = 14 + (x^2 / 4)
If h(2m) = 9m, what is one possible value of m?

My (wrong) approach:

14 + (2x^2 /4) = 9m

1) All variables in your equation are to be the same, i.e. m.

2) You need grouping symbols. You are substituting 2m in for x, so:


14 + ((2m)^2)/4 = 9m

14 + (4m^2)/4 = 9m **


.
.
.
.
2x^2 -36x + 56 = 0
(then find the values of x)

This is wrong and the values aren't ever close...

Please help :S

>
>

** 14 + (4m^2)/4 = 9m


And continue . . .