Finding the slope of P(1,3), Q(1+h,f(1+h)) where f(x)= 3x^2

[Guest]

Find the slope m, in the simplified form, of each pair of points
a) P(1,3), Q(1+h,f(1+h)) where f(x)= 3x^2

How do you do this? I have no idea. I know how to find the slope when they just give you P(1,3) and f(x)= 3x^2 , you would use the first principles formula, but why do they give you Q here?

thanks for the help

 

[pka]

\(\displaystyle \L
\begin{array}{rcl}
f(x) & = & 3x^2 \\
f(1 + h) & = & 3\left( {1 + h} \right)^2 \\
& = & 3\left( {1 + 2h + h^2 } \right) \\
\left( {1 + h,f(1 + h)} \right) & = & \left( {1 + h,3 + 6h + 3h^2 } \right) \\
\end{array}\)