Finding the Linear equation.

[Chipset3600]

Hello guys, i hv doubt in this question:

"1-Mark the point Q, such that the line through P (1, -2) and Q is perpendicular to the x axis (the horizontal axis) so that the point Q to point P is equidistant from the axis x. Find the equation of the line."


If the line be perpendicular of the X axis, so will be parallel of the Y axis. A line parallel to the axis Y can be a function?
OBS: Sorry about my bad technical English.

 

[Deleted member 4993]

Hello guys, i hv doubt in this question:

"1-Mark the point Q, such that the line through P (1, -2) and Q is perpendicular to the x axis (the horizontal axis) so that the point Q to point P is equidistant from the axis x. Find the equation of the line."


If the line be perpendicular of the X axis, so will be parallel of the Y axis. A line parallel to the axis Y can be a function?
OBS: Sorry about my bad technical English.

The answer to your question is that - A line parallel to the axis Y cannot be a function

but that is not relevant to the problem at hand.

I have few questions about the question.

so that the point Q to point P is equidistant from the axis x

What - from point P to point Q

If it is talking about the line PQ - then to be equidistant from x-axis it has to be parallel to the x-axis. Then it contradicts first requirement - the line through P (1, -2) and Q is perpendicular to the x axis.

Then

Find the equation of the line. - which line? PQ?

 

[Chipset3600]

I guess is PQ, but im doing Calculus 1 nd we are studying as function of X. I cant see the sense of this issue

The answer to your question is that - A line parallel to the axis Y cannot be a function

but that is not relevant to the problem at hand.

I have few questions about the question.

so that the point Q to point P is equidistant from the axis x

What - from point P to point Q

If it is talking about the line PQ - then to be equidistant from x-axis it has to be parallel to the x-axis. Then it contradicts first requirement - the line through P (1, -2) and Q is perpendicular to the x axis.

Then

Find the equation of the line. - which line? PQ?

 

[HallsofIvy]

Hello guys, i hv doubt in this question:

"1-Mark the point Q, such that the line through P (1, -2) and Q is perpendicular to the x axis (the horizontal axis) so that the point Q to point P is equidistant from the axis x. Find the equation of the line."


If the line be perpendicular of the X axis, so will be parallel of the Y axis. A line parallel to the axis Y can be a function?
OBS: Sorry about my bad technical English.

A line parallel to the y-axis cannot be a function. But that is irrelevant to the problem. It says nothing about a "function".

If Q is on the line through (1, -2) and the line is perpendicuar to the x- axis, then Q is of the form (1, y) for some y.