Find the limit:
Lim
x --> infinity
4x2+9x
5x2+8
Lim
x --> infinity
(4x2/x2)+(9x/x2)
(5x2/x2)+(8/x2)
Lim
x --> infinity
4+(9/x)
5+(8/x2)
Lim
x --> infinity
4 +04
5 + 0 = 5
1) Did I do this process correct?
2) Why does dividing constant by infinity will result to zero?
3) What if the answer is 4 + infinity instead of 4 + 0 .... will the answer be the same or will it be infinity?
I would appreciate any help. Thanks
Lim
x --> infinity
4x2+9x
5x2+8
Lim
x --> infinity
(4x2/x2)+(9x/x2)
(5x2/x2)+(8/x2)
Lim
x --> infinity
4+(9/x)
5+(8/x2)
Lim
x --> infinity
4 +04
5 + 0 = 5
1) Did I do this process correct?
2) Why does dividing constant by infinity will result to zero?
3) What if the answer is 4 + infinity instead of 4 + 0 .... will the answer be the same or will it be infinity?
I would appreciate any help. Thanks