finding the eccentricity or focal width of x^2 = 14y

[ericnowcool]

Hello, my first post
I have the following equation
x^2 = 14y and Im supposed to find the focal width which I understand is the same as the eccentricity,
I know that for equations like x^2/16 - y^/49 = 324 you would find c using c^2 = b^2 + a^2 and then eccentricity equals to c/a
but I don't know how to find it in this equation can someone please help?
thanks

 

[tkhunny]

Something is wrong with this question. The eccentricity of parabolas is one (1). There must be something missing, perhaps the correct defintion of "focal width"?

In this case, you may wish to consider the length of the "latus rectum".

 

[ericnowcool]

Non, that's how the question was posted, but anyway I never did find the answer since my test was the next day, it's ok though I got a good grade and now my semester is over. But if anyone can solve it, I would really appreciate it.

 

[tkhunny]

I stand by my original reply.

Look up "latus rectum" before you give up on it.