Ebba Sen Pai
New member
- Joined
- Jun 15, 2018
- Messages
- 18
Hello all. So my problem is this:
So I initially thought I had function domains down pretty well, but it seems I am lacking something important. I will try to explain my reasoning as follows:
"I can tell that for our function g(x), we must exclude all negative numbers as they will produce unhelpful imaginary numbers which don't belong in our domain.
Thus the domain of g(x) would read [0,infinity)
I can also tell that we must exclude any values of g(x) from that will produce a value of 3 in f(g(x)) since division by zero is undefined. That means 9 is excluded from g(x) as well.
Thus I would expect the domain of f(g(x)) to read [0,9)U(9,infinity).
My book/video says the domain is (9,infinity). I don't understand why values from 0 to 9 cannot be part of the domain. I see nothing stopping me from including them. Can't I plug in 4 for instance into g(x), resulting in "(2)-3" as the denominator of f(g(x))? Wouldn't that produce a negative one for the denominator which would just make the solution "-3." I don't see any way in which having 4 in the domain violates what I know is excluded.
Thank you guys for the help in advance. I really apreciate everything you guys do for me
So I initially thought I had function domains down pretty well, but it seems I am lacking something important. I will try to explain my reasoning as follows:
"I can tell that for our function g(x), we must exclude all negative numbers as they will produce unhelpful imaginary numbers which don't belong in our domain.
Thus the domain of g(x) would read [0,infinity)
I can also tell that we must exclude any values of g(x) from that will produce a value of 3 in f(g(x)) since division by zero is undefined. That means 9 is excluded from g(x) as well.
Thus I would expect the domain of f(g(x)) to read [0,9)U(9,infinity).
My book/video says the domain is (9,infinity). I don't understand why values from 0 to 9 cannot be part of the domain. I see nothing stopping me from including them. Can't I plug in 4 for instance into g(x), resulting in "(2)-3" as the denominator of f(g(x))? Wouldn't that produce a negative one for the denominator which would just make the solution "-3." I don't see any way in which having 4 in the domain violates what I know is excluded.
Thank you guys for the help in advance. I really apreciate everything you guys do for me