Finding intersection of lines (vectors)

TsAmE

Junior Member
Joined
Aug 28, 2010
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55
Find the intersection of the lines:

(7+2λ,3,177λ):λϵR)\displaystyle (7 + 2\lambda,3,-17 -7\lambda):\lambda \epsilon \mathbb{R}) and

(1λ,54λ,10+3λ):λϵR)\displaystyle (-1 - \lambda, -5 - 4\lambda,10+3\lambda):\lambda \epsilon \mathbb{R})

Attempt:

1. 7+2λ=1λ\displaystyle 7+2\lambda = -1 -\lambda

2. 3=54λ\displaystyle 3 = -5 -4\lambda

3. 177λ=10+3λ\displaystyle -17 - 7\lambda = 10 + 3\lambda

For equation 3 I got

8=4λ\displaystyle 8 =- 4\lambda

λ=2\displaystyle \lambda = -2

Now when I tried to sub in 2 for lambda in equation 1 to see if the LHS = RHS it doesnt:

7+2(2)=1(2)\displaystyle 7 + 2(-2) = -1 - (-2)
3=1\displaystyle 3 = 1

Why is this?
 
That means the lines do not intersect.

Setting the vectors equal and simplifying we get:

8+3t=0\displaystyle 8+3t=0

8+4t=0\displaystyle 8+4t=0

2710t=0\displaystyle -27-10t=0

See the first two equations?. That gives it away.
 
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