Find the intersection of the lines:
\(\displaystyle (7 + 2\lambda,3,-17 -7\lambda):\lambda \epsilon \mathbb{R})\) and
\(\displaystyle (-1 - \lambda, -5 - 4\lambda,10+3\lambda):\lambda \epsilon \mathbb{R})\)
Attempt:
1. \(\displaystyle 7+2\lambda = -1 -\lambda\)
2. \(\displaystyle 3 = -5 -4\lambda\)
3. \(\displaystyle -17 - 7\lambda = 10 + 3\lambda\)
For equation 3 I got
\(\displaystyle 8 =- 4\lambda\)
\(\displaystyle \lambda = -2\)
Now when I tried to sub in 2 for lambda in equation 1 to see if the LHS = RHS it doesnt:
\(\displaystyle 7 + 2(-2) = -1 - (-2)\)
\(\displaystyle 3 = 1\)
Why is this?
\(\displaystyle (7 + 2\lambda,3,-17 -7\lambda):\lambda \epsilon \mathbb{R})\) and
\(\displaystyle (-1 - \lambda, -5 - 4\lambda,10+3\lambda):\lambda \epsilon \mathbb{R})\)
Attempt:
1. \(\displaystyle 7+2\lambda = -1 -\lambda\)
2. \(\displaystyle 3 = -5 -4\lambda\)
3. \(\displaystyle -17 - 7\lambda = 10 + 3\lambda\)
For equation 3 I got
\(\displaystyle 8 =- 4\lambda\)
\(\displaystyle \lambda = -2\)
Now when I tried to sub in 2 for lambda in equation 1 to see if the LHS = RHS it doesnt:
\(\displaystyle 7 + 2(-2) = -1 - (-2)\)
\(\displaystyle 3 = 1\)
Why is this?