legacyofpiracy
Junior Member
- Joined
- Oct 20, 2005
- Messages
- 82
How are you supposed to determine the absolute maximum and minimum values of this fuction?
F(x)= (x-c)^2/5 when -3<x<6, 0<c<1 (all "<" are less than or equal signs)[/code]
F(x)= (x-c)^2/5 when -3<x<6, 0<c<1 (all "<" are less than or equal signs)[/code]