Finding equation of vertical asymptote(s) of the function

charlesjoy

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Mar 26, 2009
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Good afternoon. I am attempting to do the following:

1) Find the equation of the vertical asymptote(s) of the rational function:

g(x) = 8x + 9/X - 6

2) Find f(k) when: f(x) = 3x^2 + 4x + 5 (the 3x is squared)
 
First you should try to use proper formatting to show exactly what you mean:

g(x) = 8x + (9/x) - 6

or

g(x) = 8x + [9/ (x-6)]

Otherwise it can be confusing to the person trying to help you. Also, I'm assuming that x and X are the same thing.

Then, just for future reference, if you want to add an exponent to something, you use the "carrot" symbol: " ^ " so...

f(x) = (3x)^2 + 4x + 5

Then show us what your thoughts are on these problems.
 
If you mean g(x) = (8x + 9)/(x - 6), which I think is what you mean, then the vertical asymptote is where x - 6 = 0. Can you come with the equation of the vertical line?
 
charlesjoy said:
1) Find the equation of the vertical asymptote(s) of the rational function:
To learn how to find asymptotes (vertical and otherwise), try here.

Short version: Vertical asymptotes are the zeroes of the denominator.

charlesjoy said:
2) Find f(k) when: f(x) = 3x^2 + 4x + 5 (the 3x is squared)
To learn how to evaluate a function at an expression (such as "evaluating f(x) at x = k"), try here.

Short version: Whatever they want you to "evaluate" at, plug that in for every instance of "x". For instance, f(@) = 3@[sup:3d6icqny]2[/sup:3d6icqny] + 4@ + 5.

:D
 
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