finding dy/dt

[kggirl]

Find dy/dt if x = cos[t] and y = the square root of 3 and t = 2pi/3

 

[Matt]

dy/dt = 0

dy/dx = (dy/dt)/(dx/dt) = 0/sin[t] = 0

 

[kggirl]

dy/dt = 0

dy/dx = (dy/dt)/(dx/dt) = 0/sin[t] = 0

I entered the problem wrong it should be:

Find dy/dx if x = cos[t] and y = the square of 3cos[t] and t = 2pi/3

 

[Matt]

http://www.freemathhelp.com/forum/viewtopic.php?t=8494