finding domain

[maral55]

Hi

I'm new to this board and my language is not English so please forgive me for the possible mistakes.

I want to know the domain of this function

square root of [x](x-1)

I saw somewhere that the answer is x>1 and x=1, x=0

But I think that it must be x>0 and x=0
anyone knows how to put signs here?

 

[wjm11]

I want to know the domain of this function

square root of [x](x-1)

I saw somewhere that the answer is x>1 and x=1, x=0

But I think that it must be x>0 and x=0

This can be written as [x(x-1)]^(1/2). The "^" indicates the the expression following it is an exponent.

The domain requirement is that the radicand not be negative. It is okay for x to be negative in this case as long as x(x-1)>0. The only values that x cannot be, in this case, are values between 0 and 1. For example, (.5)(.5 - 1) = -.25, so x cannot be .5. Make sense?