Finding Derivatives

cole92

Junior Member
Joined
Mar 30, 2006
Messages
65
I think I am having some issues on these problems but I am not sure cause I do not know if they are all corect. I know i recently had a topic where I asked if anyone could look over my answers, and I hate to do this again, but I just want to know if I am doin it correctly.

1.h(x) = (2x^2 - 3x + 1) / x and I got h'(x) (-4x + 3) / x^2
2. y = 3x(6x-5x^2) >>> y' = 36x - 45x^2
3. f(x) = 3rd root of x + 5th root of x (Sorry I do not know how to do the notation for those :/ ) f'(x) = [1 / (3)(3rd root of x^2)] + [1 / (5)(fifth root of x^4)] ..... again sorry for lack of notation.

I have a feeling these are incorrect.
 
cole92 said:
I think I am having some issues on these problems but I am not sure cause I do not know if they are all corect. I know i recently had a topic where I asked if anyone could look over my answers, and I hate to do this again, but I just want to know if I am doin it correctly.

1.h(x) = (2x^2 - 3x + 1) / x and I got h'(x) (-4x + 3) / x^2
2. y = 3x(6x-5x^2) >>> y' = 36x - 45x^2
3. f(x) = 3rd root of x + 5th root of x (Sorry I do not know how to do the notation for those :/ ) f'(x) = [1 / (3)(3rd root of x^2)] + [1 / (5)(fifth root of x^4)] ..... again sorry for lack of notation.

I have a feeling these are incorrect.

\(\displaystyle h(x) \, = \, \frac{2x^2 - 3x +1}{x}\)

\(\displaystyle h'(x) \, = \, \frac{(4x - 3)\cdot x - (2x^2 - 3x +1)\cdot 1 }{x^2}\)
 
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