finding derivative of y = (x^3 + e^-x + 5)^(1/2)

jlaird77

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Feb 17, 2007
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Was hoping to get some help with this question. it is y=(x^3+e^-x +5)^(1/2).

I was thinking that i would use the chain rule and i came up with this answer.

3x^2-e^-x/2(x^3+e^-x +5)^1/2.

Am i close?
 
jlaird77 said:
Was hoping to get some help with this question. it is y=(x^3+e^-x +5)^(1/2).

I was thinking that i would use the chain rule and i came up with this answer.

3x^2-e^-x/2(x^3+e^-x +5)^1/2.

Am i close?

correct use of the chain rule ... please use grouping symbols for the sake of clarity.

[3x^2 - e^(-x)]/[2(x^3 + e^(-x) + 5)]^(1/2)
 
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