Hello again folks!
I am trying to find f'(x) for f(x) = ⎷(ax + b)
I can work out the following:
?y + y = ⎷[a * (x + ?x) + b]
?y = ⎷[a * (x + ?x) + b] - ⎷(ax + b)
?y = ⎷(ax + a?x + b) - ⎷(ax + b)
?y = (ax + a?x + b)1/2 - (ax + b)1/2
?y/?x = [(ax + a?x + b)1/2 - (ax + b)1/2] / ?x
At this point, I want to say that you have to multiply the numerator by something like (ax - b)1/2, but am not really sure. all help appreciated. thanks again great calculus people!!
I am trying to find f'(x) for f(x) = ⎷(ax + b)
I can work out the following:
?y + y = ⎷[a * (x + ?x) + b]
?y = ⎷[a * (x + ?x) + b] - ⎷(ax + b)
?y = ⎷(ax + a?x + b) - ⎷(ax + b)
?y = (ax + a?x + b)1/2 - (ax + b)1/2
?y/?x = [(ax + a?x + b)1/2 - (ax + b)1/2] / ?x
At this point, I want to say that you have to multiply the numerator by something like (ax - b)1/2, but am not really sure. all help appreciated. thanks again great calculus people!!