benderzfloozy
New member
- Joined
- Apr 17, 2007
- Messages
- 18
Hi. There are two statement in which I am to find a counterexample. The first:
The number n is an odd integer if and only if 3n+5 is an even integer.
Here, I assumed that n is even such that n = 2k. I inserted it into 3n+5 and came up with 6n+5. There's nothing factorable, so 3n+5 is not odd when n is even. I then tried doing the opposite, saying that n is odd. I inserted n = 2k+1 into 3n+5 and got 6n+8. 6n+8 is factorable: 2(3n+4). So, 3n+5 is even when n is odd. I can't seem to find a counterexample!
The second statement: The number n is an even integer if and only if 3n+2 is an even integer. So, I assumed the opposite. I plugged n = 2k+1 into 3n+2, and came up with 6k+5. So, when n is odd, 3n+5 is odd.
I can't seem to find a counterexample for either! Any insight is GREATLY appreciated!
The number n is an odd integer if and only if 3n+5 is an even integer.
Here, I assumed that n is even such that n = 2k. I inserted it into 3n+5 and came up with 6n+5. There's nothing factorable, so 3n+5 is not odd when n is even. I then tried doing the opposite, saying that n is odd. I inserted n = 2k+1 into 3n+5 and got 6n+8. 6n+8 is factorable: 2(3n+4). So, 3n+5 is even when n is odd. I can't seem to find a counterexample!
The second statement: The number n is an even integer if and only if 3n+2 is an even integer. So, I assumed the opposite. I plugged n = 2k+1 into 3n+2, and came up with 6k+5. So, when n is odd, 3n+5 is odd.
I can't seem to find a counterexample for either! Any insight is GREATLY appreciated!