Finding coordinates

I may give you a way of doing this that seems strange. But please try to see why it works.
The line segment is:
(t)=(1+6t, 47t)\ell (t) = (-1+6t,~4-7t) note that (0)=(1,4) & (1)=(5,3)\ell(0)=(-1,4)~\&~\ell(1)=(5,-3) so (13)=(1,53)\ell\left(\frac{1}{3}\right)=\left(1,\frac{5}{3}\right)
 
That seems more complicated than necessary! Instead of getting parametric equations for the line, think "similar triangles" which tell you that you can do the x and y coordinates separately. What number is 1/3 of the way from -1 to 5? What number is 1/3 of the way from 4 to -3?
 
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