needhelpoften!
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- Feb 3, 2009
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How to find the Asymptotes of a given equation?
a. 3^((x^2)-1)+2
b. log8(x^2-9)-1
c. y=log((x-5)/(x-7))
a. 3^((x^2)-1)+2
b. log8(x^2-9)-1
c. y=log((x-5)/(x-7))
needhelpoften! said:How to find the Asymptotes of a given equation?
a. 3^((x^2)-1)+2
b. log8(x^2-9)-1
c. y=log((x-5)/(x-7))
needhelpoften! said:Sorry...was not aware of these rules. thanks though!
All right here is where i am stuck:
a. 3^((x^2)-1)+2 ==> i know that in all exponential equations, the horizontal asymptote is 0. <<< Incorrect
Please tell us - according to your textbook/class-notes:
What is the definition of the assymptote?
It will be useful - if you plot the function using a graphing calculator (or a computer software) and study its behavior.
but whats thrwoing me off here is that "-1" and +2. Im not sure with the -1, but my guess the asymptote is y=2.
b. log8(x^2-9)-1 ==> again same thing here, i know when log(x), the asymptote is 0, but now the x^2-9 is throwing me ( i realize i must solve for that and that is my asymptote), but now what about the -1?
c. y=log((x-5)/(x-7)) ==> are there two asymptotes here, x=5 and x = 7 ........ Correct
and y=0???
see, i know the general rules,
You may know the general rules - but you are not applying those correctly.
Go back to the definition of asymptotes - and apply. Plot the functions - see whether you are thinking correctly or not.
i think, but im confused on how to apply them in situations with additional details.
thansk again for ur help!