construct a surjection of N in itself for which each integer has an infinity of antecedents
A Ayoub New member Joined Sep 7, 2020 Messages 1 Sep 7, 2020 #1 construct a surjection of N in itself for which each integer has an infinity of antecedents Last edited by a moderator: Sep 8, 2020
D Deleted member 4993 Guest Sep 7, 2020 #2 Ayoub said: construct a surjection of N in itself for which each integer has an infinity of antecedents Click to expand... Your attachment is not visible to us. Please show us what you have tried and exactly where you are stuck. Please follow the rules of posting in this forum, as enunciated at: https://www.freemathhelp.com/forum/threads/read-before-posting.109846/#post-486520 Please share your work/thoughts about this problem.
Ayoub said: construct a surjection of N in itself for which each integer has an infinity of antecedents Click to expand... Your attachment is not visible to us. Please show us what you have tried and exactly where you are stuck. Please follow the rules of posting in this forum, as enunciated at: https://www.freemathhelp.com/forum/threads/read-before-posting.109846/#post-486520 Please share your work/thoughts about this problem.
