Use the given:How much is a×b if a^2+b^2=1001 and (a-b)^2=1
Use the given:
\(a^2-2ab+b^2=(a-b)^2=1\)
\(1001=a^2+b^2=1+2ab\)
\(2ab=1001-1\)
Now finish it !
Can you explain it a bit more if you don't mindUse the given:
\(a^2-2ab+b^2=(a-b)^2=1\)
\(1001=a^2+b^2=1+2ab\)
\(2ab=1001-1\)
Now finish it !
Do you see that \(a^2-2ab+b^2=(a-b)^2=1~?\)Can you explain it a bit more if you don't mind
Yeah but how did you get that 1+2abDo you see that \(a^2-2ab+b^2=(a-b)^2=1~?\)
Add \(2ab\) to both sides of the equality.Yeah but how did you get that 1+2ab
Thanks for taking the time to helpAdd \(2ab\) to both sides of the equality.