Find the vertex and zeros(x-intercepts)

Kriston

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Jun 7, 2010
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I'm not quite sure I'm doing this problem correctly.

y=1/2x^2
the vertex is (0,0)
but when I try and find the x-intercepts I keep getting 0's and the book says otherwise
to find the x I plug in 0 for y

0= 1/2x^2 Then times each side by 2/1 to get x by its self.

2*0=x^2 I get x = 0
so when I plug that in to solve for y
y=1/2(0)^2 I get y = 0

I just don't know if I'm finding the x-intercepts because I'm not getting a parabola when everything is 0's
 
The function y=1/2x^2 definetly only intersects the x axis when x=0.

you have the problem right.
 
Kriston said:
the vertex is (0,0)
but when I try and find the x-intercepts I keep getting 0's and the book says otherwise
If vertex is (0,0) then x-intercepts are (sounds silly!) (0,0) and (0,0)...
WHAT does book say that's "otherwise"?
 
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