Find the two x-intercepts of the function f and show that f prime (x)=0

at some point between the two x-intercepts for f(x)=x(x-3)
Seriously?

What are the x-intercepts of \(\displaystyle f(x) = x(x - 3) = x^2 - 3x\)?

What is f'(x)?

For what value or values of x is f'(x) = 0?
 
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