FIND THE SOLUTION SET: X^3-8x^2-3x-90=0?

pcrcool

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Oct 9, 2013
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X^3-8x^2-3x-90=0; -5

"Use Synthetic Division to show that the number given to the right of the equation is a solution of the equation. Then solve the polynomial equation." what is the solution set? Its like 3 number separated by commas.

Thanks
 
Something wrong with that equation: CHECK IT! It's probably + 90, not - 90 \(\displaystyle \ \ \ \) Changing it from "+ 90" to " - 90+" doesn't make the result even near 0.

And show your work: NO homework done here...

NOPE, its -90. The problem is correct .


That is not true. The problem is not correct as stated. Staying as close to the magnitude of the coefficients/constants and the same degrees

of the variable, keeping the constant as -90 (actually, subtracting 90) ,and the given solution as x = -5, the closest that the problem could be correctly stated is as


\(\displaystyle x^3 + 8x^2 - 3x - 90 \ = 0; \ \ \ -5\)
 
Last edited:
(x^3 - 8x^2 - 3x + 90) / (x - 5) = x^2 - 3x - 18

Should have mentionned that problem should PROBABLY be:

x^3 - 8x^2 - 3x + 90 = 0; +5 (instead of X^3-8x^2-3x-90=0; -5)




Okay wait, thats what it is, it is +90, but not -8x^2, so its: X^3+8x^2-3x-90=0

Sorry my bad. I copied it wrong. So anywho, its: X^3+8x^2-3x-90=0; -5
 
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