Find the slope of the line

[flora33]

Hello all, I'm having trouble with how to do this problem:

3x = 4y - 2

I know that I need to find the coordinates of two points on the line, and I know that you can replace the x or y with a 0, but I'm not sure how to do it when one variable is on each side of the equation. Any help is greatly appreciated!

Flora

 

[royhaas]

Solve for y.

 

[masters]

Are you familiar with the slope-intercept form of a linear equation?

It is in the form: y = mx + b

m = slope and b = y-intercept (where the line crosses the y-axis)

So, convert 3x = 4y - 2 into slope intercept form and see what the coefficient of x turns out to be. That will be your slope.

If you need to find two points on the graph, use (0, b) which is your y-intercept for one of the points. Then let y = 0 in your original equation and solve for x. This will be the x - intercept (x, 0).

 

[flora33]

Are you familiar with the slope-intercept form of a linear equation?

It is in the form: y = mx + b

m = slope and b = y-intercept (where the line crosses the y-axis)

So, convert 3x = 4y - 2 into slope intercept form and see what the coefficient of x turns out to be. That will be your slope.

If you need to find two points on the graph, use (0, b) which is your y-intercept for one of the points. Then let y = 0 in your original equation and solve for x. This will be the x - intercept (x, 0).

No, I'm not familiar with that, it might be something we are covering this week, but not yet. I'm trying to figure out how I would convert the problem to your formula:
4y = 3x - 2? That probably isn't right, I don't know though because I haven't used that formula yet!
So, I did try to find the two points by using (0, b)

3x = 4(0) - 2
3x = -2
3x/3 and -2/3
Would it be x = -2/3, so the coordinates would be (0,-2/3) ???

Then, wouldn't you do the same, by solving for y?

3(0) = 4y - 2, this is where I'm not sure do I replace y with a number here, or what is the next step?

 

[skeeter]

the goal is to solve for y.

3x = 4y - 2

add 2 to both sides ...

3x + 2 = 4y

divide every term by 4 ...

(3/4)x + (1/2) = y

or ...

y = (3/4)x + (1/2)

your linear equation is now in the slope-intercept form, y = mx + b, where m = slope and b = the y-intercept.

 

[Deleted member 4993]

Hello all, I'm having trouble with how to do this problem:

3x = 4y - 2

I know that I need to find the coordinates of two points on the line, and I know that you can replace the x or y with a 0, but I'm not sure how to do it when one variable is on each side of the equation. Any help is greatly appreciated!

Flora

I think we are making the problem a little more complicated than it is intended.

S/he has been asked to find two points, so that those satisfy the given equation.

Let x= 0, then

3 * 0 = 4y - 2

y = 1/2

One of the points is (0, 1/2)

for the other point,

Let y = 0, then

3 * x = 4*0 - 2

x = - 3/2

The other point is (-3/2, 0)

 

[flora33]

Hello all, I'm having trouble with how to do this problem:

3x = 4y - 2

I know that I need to find the coordinates of two points on the line, and I know that you can replace the x or y with a 0, but I'm not sure how to do it when one variable is on each side of the equation. Any help is greatly appreciated!

Flora

I think we are making the problem a little more complicated than it is intended.

S/he has been asked to find two points, so that those satisfy the given equation.

Let x= 0, then

3 * 0 = 4y - 2

y = 1/2

One of the points is (0, 1/2)

for the other point,

Let y = 0, then

3 * x = 4*0 - 2

x = - 3/2

The other point is (-3/2, 0)

Subhotosh,

Thanks for your posting. It turns out I was overthinking it too. I think I've got it now. Thanks again!