find the root of the function

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dayton1

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Oct 22, 2007
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Ok one more today...thanks all for your help. It feels like this instructor gave us problems meant to confuse, if everyone in the class failed :x

g(x)= (24x-4x^3-10x^2)/4x+16 *find the root of the function

=2x(12-2x^2-5x)/4(x+4)

= 2x(-2x^2-5x+12)/4(x+4)

* ok at this point I get confused. Can I reduce the numerator 2x and the denominator 4? I am not sure what to do next, or if I even did it correctly up to this point.
 
dayton1 said:
Ok one more today...thanks all for your help. It feels like this instructor gave us problems meant to confuse, if everyone in the class failed :x

g(x)= (24x-4x^3-10x^2)/4x+16 *find the root of the function

=2x(12-2x^2-5x)/4(x+4)

= 2x(-2x^2-5x+12)/4(x+4)

* ok at this point I get confused. Can I reduce the numerator 2x and the denominator 4? I am not sure what to do next, or if I even did it correctly up to this point.
Click to expand...

Put parenthesis to group your operations. Other than that you have done it correctly.

Now - go ahead and find the roots.
 
Whoops I meant

[x(-2x-8)(3x+12)]/[2x+8]

[x(2x+8)(3x+12)]/[2x+8]

cancel the 2x+8

x(3x+12)=0
 
dayton1 said:
Whoops I meant

[x(-2x-8)(3x+12)]/[2x+8]<-----You havenot factorized correctly

[x(2x+8)(3x+12)]/[2x+8]

cancel the 2x+8

x(3x+12)=0
Click to expand...

However - after factorizing correctly - you can reduce to find the roots.
 
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