Find the locus of points (x,y,z) such that vector from (2,−1,4) to (x,y,z) is...

[me do]

Find the locus of points (x,y,z) such that vector from (2,−1,4) to (x,y,z) is...

Hi,
I'm new and I don't know if this the correct place to send my problem.
Any way ,please solve this prob.

* Find the locus of points (x,y,z) such that a vector from point (2,−1,4) to point (x,y,z) will always be perpendicular to the vector from (2,−1,4) to (3,3,2).

Thank you

 

[Deleted member 4993]

Hi,
I'm new and I don't know if this the correct place to send my problem.
Any way ,please solve this prob.

* Find the locus of points (x,y,z) such that a vector from point (2,−1,4) to point (x,y,z) will always be perpendicular to the vector from (2,−1,4) to (3,3,2).

Thank you

What are your thoughts?

Please share your work with us ...even if you know it is wrong.

If you are stuck at the beginning tell us and we'll start with the definitions.

You need to read the rules of this forum. Please read the post titled "Read before Posting" at the following URL:

http://www.freemathhelp.com/forum/announcement.php?f=33

 

[tkhunny]

Hi,
I'm new and I don't know if this the correct place to send my problem.
Any way ,please solve this prob.

* Find the locus of points (x,y,z) such that a vector from point (2,−1,4) to point (x,y,z) will always be perpendicular to the vector from (2,−1,4) to (3,3,2).

Thank you

Perhaps there is a dot-product in your future?

 

[Steven G]

Hi,
I'm new and I don't know if this the correct place to send my problem.
Any way ,please solve this prob.

* Find the locus of points (x,y,z) such that a vector from point (2,−1,4) to point (x,y,z) will always be perpendicular to the vector from (2,−1,4) to (3,3,2).

Thank you

I have to comment on your post. You wrote Any way ,please solve this prob. Are you kidding? You want us to do your work without you participating? I suggest you do a google search for online paid tutoring or read the policy of the forum and follow those rules. The choice is your and personally I hope you choose to stay with the forum.