find the limit

[spacewater]

problem
$\displaystyle \frac{lim}{?x->0} \frac{sin[(\pi/6)+?x]-( \frac{1}{2})}{?x}$ (Find the limit when ?x approaches 0)
Steps
$\displaystyle \frac{sin(\pi/6)cos?x+cos(\pi/6)sin?x-(1/2)}{?x}$
$\displaystyle \frac {1/2cos?x+\sqrt3/2sin?x-1/2}{?x}$

this is where I got stuck... 1/2 * cos(0) +$\displaystyle \sqrt3$/2*sin(0) - 1/2 = 1/2-1/2 = 0
Can someone point out where I went wrong on this equation please?

 

[BigGlenntheHeavy]

$\displaystyle Where \ you \ got \ stuck: \ \lim_{\Delta x\to0}\frac{cos(\Delta x)+\sqrt3sin(\Delta x)-1}{2\Delta x}$

$\displaystyle As \Delta x \ approaches \ 0. \ we \ get \ the \ indeterminate \ form \ \frac{0}{0}, \ hence \ a \ job \ for \ the \ Marqui.$