1. lim (3x^3 + 2x-1)/2x^4-3x^3-2) as x-->+ infinity.
W wonky-faint New member Joined Aug 28, 2006 Messages 17 Sep 19, 2006 #2 it would be 0 because the power of x in the denominator is greater than that in the numerator.
stapel Super Moderator Staff member Joined Feb 4, 2004 Messages 16,582 Sep 20, 2006 #3 Re: Find the limit interval said: 1. lim (3x^3 + 2x-1)/(2x^4-3x^3-2) as x-->+ infinity. Click to expand... Try dividing top and bottom by 1/x<sup>4</sup>. You'll get a bunch of terms that go to zero, except for the 2. And 0/2 = 0. Eliz.
Re: Find the limit interval said: 1. lim (3x^3 + 2x-1)/(2x^4-3x^3-2) as x-->+ infinity. Click to expand... Try dividing top and bottom by 1/x<sup>4</sup>. You'll get a bunch of terms that go to zero, except for the 2. And 0/2 = 0. Eliz.