Find the limit of (3x^3 + 2x-1)/2x^4-3x^3-2) as x -> inft

it would be 0 because the power of x in the denominator is greater than that in the numerator.
 
Re: Find the limit

interval said:
1. lim (3x^3 + 2x-1)/(2x^4-3x^3-2) as x-->+ infinity.
Try dividing top and bottom by 1/x<sup>4</sup>. You'll get a bunch of terms that go to zero, except for the 2. And 0/2 = 0.

Eliz.
 
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