Find the least common multiple of the x and y intercepts described by 8y+12y=336
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I'll assume this is supposed to be: 8x + 12y = 336
The x intercept is found by setting y equal to 0: 8x = 336 ---> x = 42
The y intercept is found by setting x equal to 0: 12y = 336 ---> y = 28
There is a standard technique for finding the LCM by first breaking each of these numbers into their prime factors:
42 = 2 * 3 * 7
28 = 2 * 2 * 7
To find the LCM, you have to observe the maximum number of times each prime factor appears in each breakout, and multiply them together:
two 2s from the "28"
one 3 from the "42"
one 7 from "either"
So:
2 * 2 * 3 * 7 = 84
Steve
