Find the inverse of the function f(x) = 5IN(7-3x)

G

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Guest
This one involves the natural log, I think.

Find the inverse of f(x) = 5IN(7-3x).

I need some tips.
 
Re: f(x) = 5IN(7-3x)

interval said:
Find the inverse of f(x) = 5*ln(7-3x).
y = 5*ln(7-3x)

Swap.

x = 5*ln(7-3y)

Solve

x/5 = ln(7-3y)

\(\displaystyle e^{x/5} = 7-3y\)

\(\displaystyle 3y = 7 - e^{x/5}\)

\(\displaystyle y = (1/3)*[7 - e^{x/5}] = f^{-1}(x)\)
 
interval said:
This one involves the natural log.... f(x) = 5IN(7-3x).
Note: The abbreviation for "natural log" is "ln"; that is, a lower-case ell-enn.

Eliz.
 
ok

Liz,

Thanks for letting me know about In not IN.

tkhunny,

Thanks for your help.

Does it mater if I write e^x/5 - 7 or does it have to be 7 - e^x/5?
 
Re: ok

interval said:
Does it mater if I write e^x/5 - 7 or does it have to be 7 - e^x/5?

does a - b = b - a if a and b are not equal to each other?
 
Re: ok

interval said:
Does it mater if I write e^x/5 - 7 or does it have to be 7 - e^x/5?
It matters if it is e^x/5 of e^(x/5).
 
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