superevilcube
New member
- Joined
- Feb 8, 2007
- Messages
- 4
I need to find the inverse of the following function. I think I am on the right track, so I wills how my work.
\(\displaystyle f(x)=\L \frac{x}{sqrt{x^2+7}}\)
I then switched out the variables and began to solve for \(\displaystyle y\)
\(\displaystyle x = \L \frac{y}{sqrt{y^2+7}}\)
\(\displaystyle x{sqrt{y^2+7}} = y\)
\(\displaystyle x^2(y^2+7) = y\)
\(\displaystyle x^2y^2+7x^2 = y\)
\(\displaystyle x^2y^2 = y-7x^2\)
\(\displaystyle x^2y^2-y = -7x^2\)
\(\displaystyle y(x^2y-1) = -7x^2\)
Am I on the right track? If so, what do I do next? (I'm completely stumped).
I know the answer is the following, so that's what I think I'm on the right tract:
\(\displaystyle f^-^1(x)=\L \frac{{sqrt{7}}x}{sqrt{1-x^2}}\) , -1< x <1
\(\displaystyle f(x)=\L \frac{x}{sqrt{x^2+7}}\)
I then switched out the variables and began to solve for \(\displaystyle y\)
\(\displaystyle x = \L \frac{y}{sqrt{y^2+7}}\)
\(\displaystyle x{sqrt{y^2+7}} = y\)
\(\displaystyle x^2(y^2+7) = y\)
\(\displaystyle x^2y^2+7x^2 = y\)
\(\displaystyle x^2y^2 = y-7x^2\)
\(\displaystyle x^2y^2-y = -7x^2\)
\(\displaystyle y(x^2y-1) = -7x^2\)
Am I on the right track? If so, what do I do next? (I'm completely stumped).
I know the answer is the following, so that's what I think I'm on the right tract:
\(\displaystyle f^-^1(x)=\L \frac{{sqrt{7}}x}{sqrt{1-x^2}}\) , -1< x <1