Find the inverse laplace transform

H

hardyaa1

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Jul 13, 2009
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F(s) = ( 4s^3 - 3s^2 + 6s + 10 ) / ( s^2 ( s^2 - 2s + 5 ))

sorry i can't give you a specific part where i'm messing this one up, i just don't know how to factor it into things i can calculate... we get to use a table that gives a few basic laplace transforms, but i haven't been able to get it simplified enough. Maybe this requires partial fractions?
 
hardyaa1 said:
F(s) = ( 4s^3 - 3s^2 + 6s + 10 ) / ( s^2 ( s^2 - 2s + 5 ))

sorry i can't give you a specific part where i'm messing this one up, i just don't know how to factor it into things i can calculate... we get to use a table that gives a few basic laplace transforms, but i haven't been able to get it simplified enough. Maybe this requires partial fractions?
Click to expand...

It does require breaking into partial fractions:

( 4s^3 - 3s^2 + 6s + 10 ) / ( s^2 ( s^2 - 2s + 5 )) = A/s + B/s^2 + (Cs + D)/(s^2 - 2s + 5)
 
Thanks... that's what I was thinking. I'm pretty sure I got to the right answer. I really like your Neumann quote btw.
 
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