\int x^5e^{1-x^6} dx I know u=1-x^6 and du= -6x^5 dx what should be my next step?
S Stud778 New member Joined Jun 10, 2010 Messages 3 Jun 10, 2010 #1 \(\displaystyle \int x^5e^{1-x^6} dx\) I know \(\displaystyle u=1-x^6\) and \(\displaystyle du= -6x^5 dx\) what should be my next step?
\(\displaystyle \int x^5e^{1-x^6} dx\) I know \(\displaystyle u=1-x^6\) and \(\displaystyle du= -6x^5 dx\) what should be my next step?
D Deleted member 4993 Guest Jun 10, 2010 #2 Stud778 said: \(\displaystyle \int x^5e^{1-x^6} dx\) I know \(\displaystyle u=1-x^6\) and \(\displaystyle du= -6x^5 dx\) what should be my next step? Click to expand... \(\displaystyle \int x^5e^{1-x^6} dx \ \ = \ \ \int e^{1-x^6} (x^5 dx) \ \ = \ \ \int e^{u} \cdot (-\frac{du}{6})\) Now continue....
Stud778 said: \(\displaystyle \int x^5e^{1-x^6} dx\) I know \(\displaystyle u=1-x^6\) and \(\displaystyle du= -6x^5 dx\) what should be my next step? Click to expand... \(\displaystyle \int x^5e^{1-x^6} dx \ \ = \ \ \int e^{1-x^6} (x^5 dx) \ \ = \ \ \int e^{u} \cdot (-\frac{du}{6})\) Now continue....
