Find the Integers

greatwhiteshark

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May 8, 2005
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There are three consecutive multiples of nine. The sum of the first two numbers is 2,853. What are the integers?
 
Hello, Janet!

There are three consecutive multiples of nine.
The sum of the first two numbers is 2,853.
What are the integers?
A multiple of 9 is of the form: .9n, .for some integer n.

The first number is: . 9k
The next number is: . 9(k + !)

Can you set up the equation and solve it now?
 
help

There are three consecutive multiples of nine.
The sum of the first two numbers is 2,853.
What are the integers?


A multiple of 9 is of the form: .9n, .for some integer n.

The first number is: . 9k
The next number is: . 9(k + 1)

What is the equation?
 
Janet, are you REALLY trying?
Problem states that 2 numbers = 2853;
Soroban tells you these 2 numbers are 9k and 9(k+1):
so equation is 9k + 9(k+1) = 2853 : now solve for k.
 
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