Find the equation, in slope-intercept form.........

[Tresa332006]

I need to find the equation, in slope-intercept form, of line that passes through the points(5,6) and (-7,3).

I know I must first find the slope of the line

3-6/-7-(-5)

-3/12

ok I've done that
now What I do next is

y-6= -3/12(x + 5)
y-6= -3/12x -15/12
ok I'm not sure if I have done this correctly or if I am all wrong. Can someone please help me. I just need to know what steps are next?

 

[stapel]

I need to find the equation, in slope-intercept form, of line that passes through the points(5,6) and (-7,3). I know I must first find the slope of the line: 3-6/-7-(-5)...

Is the first point supposed to be "(-5, 6)" or "(5, 6)"?

Thank you.

Eliz.

 

[Tresa332006]

I need to find the equation, in slope-intercept form, of line that passes through the points(5,6) and (-7,3). I know I must first find the slope of the line: 3-6/-7-(-5)...

Is the first point supposed to be "(-5, 6)" or "(5, 6)"?

Thank you.

Eliz.

Eliz, It is suppose to be (5,6) I was looking at the other problem that I was working with that had -5.

 

[stapel]

It is suppose to be (5,6)

Then re-work the exercise, because it would appear that you used "-5" (instead of "5") in your computations.

Eliz.

 

[Tresa332006]

It is suppose to be (5,6)

Then re-work the exercise, because it would appear that you used "-5" (instead of "5") in your computations.

Eliz.

ok Eliz. I reworked the problem and I got -3/-12

could you please tell me what I am doing wrong?

 

[Mrspi]

I need to find the equation, in slope-intercept form, of line that passes through the points(5,6) and (-7,3).

I know I must first find the slope of the line

3-6/-7-(-5)

-3/12

ok I've done that
now What I do next is

y-6= -3/12(x + 5)
y-6= -3/12x -15/12
ok I'm not sure if I have done this correctly or if I am all wrong. Can someone please help me. I just need to know what steps are next?

Ok...the slope would be

(3 - 6)/(-7 - 5)

-3/(-12)
or,
1/4

Now, use the slope of 1/4 in the point-slope form of the equation of a line. I'll use the point (5, 6):

y - 6 = (1/4)(x - 5)

This is the equation of the line....you can "manipulate" this equation to be in the form you need (like slope-intercept or standard form)

 

[Tresa332006]

Thank you a lot I am really struggling with this algebra. It is kicking my butt.