Find the domain of the function f(x) = sqrt(x + 3)

[NEHA]

Find the domain of the function defined by the equation f(x) = sqrt(x + 3)

I did the following:

. . .f(x) = sqrt( x + 3)
. . .f(3) = sqrt( (3) + 3 )
. . .f(10) = sqrt6 = 2.45

:?:

 

[skeeter]

domain of the function \(\displaystyle \L f(x) = \sqrt{x+3}\) is \(\displaystyle \L x \geq -3\).

looks like you might need more info ...

http://www.analyzemath.com/DomainRange/DomainRange.html

go and learn.

 

[NEHA]

ok thanks
so
-3 , + infinity

 

[stapel]

ok thanks

Do you understand why the answer is what it is?

Eliz.

 

[NEHA]

yes now i understand by looking at the site that skeeter gave me

 

[sujoy]

well it is when x>- 3 only then the matter within the square root is positive& you may find the root[not imaginary]
when x = -3 then it is 0 sqrt (0)=0