G
Guest
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Find f'(x) if it is known that
dxd[f(2x)]=x2
I let u(x) = 2x, then
dxd[f(u)]=dudydxdu
dxd[f(2x)]=2dudy
therefore
dudy=21x2
then
f′(x)=dxdy=dudydxdu
=(21x2)(2)
=x2
why doesn't this work??
dxd[f(2x)]=x2
I let u(x) = 2x, then
dxd[f(u)]=dudydxdu
dxd[f(2x)]=2dudy
therefore
dudy=21x2
then
f′(x)=dxdy=dudydxdu
=(21x2)(2)
=x2
why doesn't this work??