Find the derivative of y with respect to x.

teamsoulglo

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Feb 28, 2007
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Find the derivative of y with respect to x.

y= x ln (x)/ 4+ ln (x)

I can't seem to get the right answer. I've tried:

dy/dx=(4+lnx)(lnx+1)-(xlnx)(1/x) / ( 4+lnx)^2

=4lnx+4+(lnx)^2+lnx-lnx / (4+lnx)^2

=4lnx +4+(lnx)^2/ (4+lnx)^2

I submitted that and it came up incorrect. Any suggestions? I would appreciate it.
 
Is this your problem:

\(\displaystyle \L\\\frac{d}{dx}\left[\frac{xln(x)}{4+ln(x)}\right]\)?.

If so, your answer is correct.

\(\displaystyle \L\\\frac{(ln(x))^{2}+4ln(x)+4}{(ln(x)+4)^{2}}\)

The computer may expect your answer in some other, but equivalent, form.
 
This is the original problem:

Find the derivative of y with respect to x.
y= x ln (x)/ 4+ ln (x)
 
teamsoulglo said:
This is the original problem:
Find the derivative of y with respect to x.
y= x ln (x)/ 4+ ln (x)
Don't you understand? The way you wrote it we do not know for sure what goes with what. Please at least use some grouping symbols.
 
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