Find the derivative of y= ( 3 + 2/t ) / (3 - 2/t)

kimmy_koo51

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Sep 19, 2006
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Find the derivative of y= ( 3 + 2/t ) / (3 - 2/t)

I moved this around to get

y = (3 + t^-2) / (3 - t^-2 )

Is that correct?
 
It is just middle school algebra:
\(\displaystyle \L y = \frac{{3 + \frac{2}{t}}}{{3 - \frac{2}{t}}}\quad \Rightarrow \quad y = \frac{{3t + 2}}{{3t - 2}}\)
 
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