Find the derivative of ( (3x - 1)^2 - 1 )/( (3x - 1)^2 + 1 )

[kimmy_koo51]

Find the derivative of y= (3x - 1)^2 - 1/(3x - 1)^2 + 1.

 

[Johnwill]

Re: Find the derivative of ( (3x - 1)^2 - 1 )/( (3x - 1)^2 +

Find the derivative of y= (3x - 1)^2 - 1/(3x - 1)^2 + 1.

looks like you need to use power, chain and quotient rule

 

[kimmy_koo51]

In that order?

 

[Johnwill]

somewhat ..

wouldn't you first take the dy/dx of (3x - 1)^2 would be 2(3x-1)*(3) see?

 

[kimmy_koo51]

I know how to do this stuff...I just haven't had a question with so much all in one before. I am drawing a blank....could you help me out a little further if it wouldn't be a problem.

 

[Johnwill]

well basically you just have to take the dy/dx:

i.e:
========================
dy/dx (3x - 1)^2

dy/dx 1/(3x - 1)^2 &

dy/dx 1
========================


.................................................
dy/dx (3x - 1)^2 = 2(3x-1) *3

dy/dx 1/(3x - 1)^2 use the quotient rule here....(srry )

and dy/dx 1 is 0 as it's a constant.




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If i'm wrong please feel free to correct me

 

[kimmy_koo51]

..thanks very much.

 

[Johnwill]

You're Welcome