find the center of a parametric conic equation
- Thread starter Sulai
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Steven G
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What have you tried? What is the definition of the locus for this equation? If you have been asked to do this problem you should have some idea what to do. Please show us your work. If it has an error or is incomplete then helpers here will give you some hints to get you back on track. However no one here will do the work for you.
I've tried getting the x coordinate for the center by completing the square "(x-3/2)^2" so the center for all the conics from the equation is (1.5,y), this makes sense with the graph on desmos so i assume this is correct.
the locus for the equation is the set of all points that satisfy a condition (the condition being that all the points are the center of the set of conics from (k+1)x^2+ky^2+2kxy-3x+2-k=0 )
now i don't know if the x coordinate that i found is correct or how to find the y coordinate, i assume it has something to do with the "xy" term but i don't know how to tackle it
the locus for the equation is the set of all points that satisfy a condition (the condition being that all the points are the center of the set of conics from (k+1)x^2+ky^2+2kxy-3x+2-k=0 )
now i don't know if the x coordinate that i found is correct or how to find the y coordinate, i assume it has something to do with the "xy" term but i don't know how to tackle it