Find the area of a regular hexagon whose....

[Paradox]

I don't think I'm understanding this chapter in my text book. On my homework, one of the problems says: Find, to the nearest tenth, the area of a regular hexagon whose

a) side is 6

b) side is 8

c) apothem is 6

d) apothem is 8

I know that the formula for the area of a regular polygon is: 1/2ap, where a stands for the apothem and p stands for the perimeter.

Are all the angles on a regular polygon equal to 60? I think I can figure this out if so.

 

[stapel]

It is my understanding that "regular", by definition, requires that all side-lengths must be equal and all angles must be equal.

Eliz.

 

[Paradox]

But... are they all 60 degrees??

 

[Denis]

Re: Areas of Regular Polygons - are each of the angles = to

Are all the angles on a regular polygon equal to 60? I think I can figure this out if so.

Do you mean regular "hexagon"?

 

[Paradox]

Well... a regular hexagon is still a regular polygon, isn't it? I'm so confused.
Can somebody just explain to me how I go about doing this problem?